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What is the value of "a" in the following quadratic? (Make sure the equation is in
standard form: ax² + bx+c=0)
x^2 + 28 = -11x

Respuesta :

981083

Answer: a= - [tex]\frac{b}{x}[/tex]- [tex]\frac{c}{x2}[/tex]

Step-by-step explanation:

1. Move all terms not containing [tex]\alpha[/tex] to the right side of the equation.

[tex]\alpha[/tex][tex]x^{2}[/tex]=-bx-c

2. Divide each term in [tex]\alpha x^{2}[/tex]=-bx-c by [tex]x^{2}[/tex] and simplify.

a= - [tex]\frac{b}{x}[/tex] - [tex]\frac{c}{x^{2} }[/tex]

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