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What is the equilibrium constant K at 25°C for an electrochemical cell when E° = +0.0140 V and n = 2?(F = 96,500 J/(V･mol), R = 8.314 J/(mol･K))

Respuesta :

pstnonsonjoku

The equilibrium constant of the electriochmeical cell as shown is  2.976.

What is the equilibrium constant?

The equilibrium constant of a reaction shows the extent of the conversion of the reactants to products.

Now we know that;

ΔG = -nFE°cell

n = 2

F = 96,500 J/(V･mol)

E°cell = +0.0140 V

ΔG = -(2 *  96,500  * 0.0140)

ΔG = -2702 J

But;

ΔG = -RTlnK

lnK = -(ΔG/RT)

K = e^[-(ΔG/RT))

K = e^[-(( -2702)/8.314 * 298]

K = 2.976

Learn more about equilibrium constant: https://brainly.com/question/10038290

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