The pressure amplitude of a 2.80 kHz sound wave is mathematically given as
pm=0.14647pa
What is the pressure amplitude of a 2.80 kHz sound wave in the air?
Generally, the equation for the relation b/w pressure amplitude and displacement amplitude is mathematically given as
pm=2\pifvps
Therefore
pm=(2\pi)(2.80*10^3)(340)(1.225)(2.00*10^{-8})
pm=0.14647pa
In conclusion
pm=0.14647pa
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