Respuesta :

semsee45

Answer:

[tex]g(-3)=7[/tex]

[tex]g(0)=7[/tex]

[tex]g(5)=\dfrac15[/tex]

Step-by-step explanation:

[tex]g(x) =\begin{cases}7 & \text{if } x \leq 0 \\ \\\dfrac{1}{x} & \text{if } x > 0\end{cases}[/tex]

This means:

  • when x is equal to zero or less than zero, g(x) will always be 7.
  • when x is more than zero, g(x) is [tex]\frac{1}{x}[/tex]

[tex]\implies g(-3)=7[/tex]

[tex]\implies g(0)=7[/tex]

[tex]\implies g(5)=\dfrac15[/tex]

[tex]\sf\f(x)=\grey{\begin{cases}\rm 7\quad ,x\geqslant 0\\ \rm \dfrac{1}{x}\quad ,x>0\end{cases}}[/tex]

So

  • -3,0 ≤0
  • 5>0

Hence

  • g(-3)=g(0)=7
  • g(5)=1/5

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