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Part D
Calculate the following for test tube 1 and for test tube 2, and record the results in the table:

the number of moles of copper(II) sulfate used (Use 159.60 grams/mole as the molar mass of copper(II) sulfate.)
the heat absorbed by the water, in joules (Use Q = mCΔT, where 10.0 milliliters of water has a mass of 10.0 grams. Use 4.186 joules/gram degree Celsius as water’s specific heat capacity.)
the change in internal energy of the copper(II) sulfate (Assume that the energy released by the copper(II) sulfate is absorbed by the water.)
the reaction enthalpy, in joules/mole

Respuesta :

mickymike92

The heat lost by copper(ii) sulfate is equal to heat absorbed by water since the total energy in the system remains constant according to the law of conservation of energy.

How can the number of moles be determined?

The number of moles of a substance is determined using the formula below:

  • Number of moles = mass/molar mass

Assuming the mass of copper(ii) sulfate used is Mc, number of moles of copper(ii) sulfate used is:

  • Moles of copper(ii) sulfate = Mc/159.60 moles

The heat absorbed by water is calculated using the formula below:

  • Quantity of Heat, H = mass × specific heat capacity × temperature change

mass of water = 10 g

Let temperature change be Tc

Heat absorbed by water = 10 × 4.186 × Tc = 41

86Tc

The change in internal energy, ΔU of copper(ii) sulfate, is given as:

  • ΔU = Q − W

where:

Q =  heat absorbed by water

W  =  work done by or on the system

The enthalpy of the reaction is given as:

  • ΔH= energy released or absorbed/moles of copper (ii) sulfate

Therefore, according to the law of conservation of energy, the total energy in the system remains constant.

Learn more about internal energy change at: https://brainly.com/question/14126477

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