Respuesta :
Let's see
#a
Take 28
- (28)²
- (30-2)²
- 30²-2(30)(2)+2²
- 900-120+4
- 780+4
- 784
#2
Take 9,10
- 9³+10³
- (9+10)(9²-9×10+10²)
- (19)(81-90+100)
- 19(181-90)
- 19(91)
- 1729
Answer:
Two-digit number greater than 25: 32
Rewrite 32 as the difference of 2 numbers: 40 - 8
Therefore, x = 40 and y = 8
[tex]\begin{aligned}\implies (40-8)^2 & =40^2-2(40)(8)+8^2\\ & = (4 \cdot 10)^2-(80)(8)+64\\ & = 4^2 \cdot 10^2-640+64\\ & = 16 \cdot 100-640+64\\ & = 1600-640+64\\ & = 960+64\\ & = 1024\end{aligned}[/tex]
Let a = 10
Let b = 11
[tex]\begin{aligned}\implies 10^3+11^3 & =(10+11)(10^2-10 \cdot 11+11^2)\\& = 21(100-110+121)\\ & = 21(-10+121)\\ & = 21(111)\\& = 21 (100 + 10 + 1)\\ & = (21 \cdot 100)+(21 \cdot 10)+(21 \cdot 1)\\ & = 2100 +210+21\\ & = 2310 + 21\\ & = 2331\end{aligned}[/tex]