Step-by-step explanation:
I’m assuming that you’re asking about quadratic equations, but suffice it to say that the method may even work for polynomials of higher degrees.
Let’s take an example. You have x^2+6x+8.
First, multiply the term in x^2 with the constant; in this case we get 8x^2.Next, break the value in x into two numbers, such that when you add them, the value becomes that of the middle term and when you multiply them, the value becomes that which you have just calculated.
Step 1:
x^2 * 8= 8x^2
Step 2:
(break the middle term)
x^2+4x+2x+8 (notice how 4x when added to 2x gives 6x but when multiplied, gives 8x^2)
Step 3:
(separate the common terms)
x(x+4)+2(x+4)
(x+2)(x+4)
