how do I work this out?

Answer:
a. 0.41
b. 0.22
Step-by-step explanation:
The sum of probabilities over all outcomes is 1. This fact can be used to fill the table. The other questions can be answered by reference to the table.
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The total of all probabilities is 1:
k +0.23 +0.18 +0.26 +2k = 1
3k = 0.33 . . . . . . . collect terms, subtract 0.67
k = 0.11 . . . . . . . divide by 3
2k = 0.22 . . . . find 2k
Then the table is ...
[tex]\begin{array}{c|ccccc}n&1&2&3&4&5\\p(n)&0.11&0.23&0.18&0.26&0.22\end{array}[/tex]
Landing on 2 or 3 are mutually exclusive outcomes, so the probability of one or the other is the sum of their individual probabilities:
p(2 or 3) = 0.23 +0.18
p(2 or 3) = 0.41
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The table tells us ...
p(5) = 0.22