Answer:
The probability that the coin lands heads up once and tails up twice is .375, or 3/8.
Step-by-step explanation:
Check the conditions for a binomial distribution problem:
We need to use combinations to determine the probability of getting one success (one head) and two failures (two tails).
The combination would be 3 choose 1: [tex]p = {3 \choose 1} (.5)^1(.5)^2[/tex].
There is one success and two failures, denoted by the superscripts above the probability p = .5.
Use a calculator to evaluate and we get:
The probability that the coin lands heads up once and tails up twice is .375, or 3/8.