[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$550\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill &6 \end{cases} \\\\\\ A=550e^{0.03\cdot 6}\implies A=550e^{0.18}\implies A\approx 658.47[/tex]
