Answer:
4/3
Step-by-step explanation:
Given:
[tex]\displaystyle \large{\left(\dfrac{9}{16}\right)^{-\dfrac{1}{2}}}[/tex]
From the law of exponent:
[tex]\displaystyle \large{a^{-\frac{1}{2}}=\dfrac{1}{\sqrt{a}}}[/tex]
Convert to the form above:
[tex]\displaystyle \large{\left(\dfrac{9}{16}\right)^{-\dfrac{1}{2}}=\dfrac{1}{\sqrt{\dfrac{9}{16}}}}\\\displaystyle \large{\left(\dfrac{9}{16}\right)^{-\dfrac{1}{2}}=\dfrac{1}{\dfrac{3}{4}}}\\\displaystyle \large{\left(\dfrac{9}{16}\right)^{-\dfrac{1}{2}}=\dfrac{4}{3}}[/tex]
Therefore, the solution is 4/3
