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A body starts from rest and travels with uniform acceleration of 2 m/s², if its velocity is v after making a displacement of 9 m . Then find the value of v .​

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Question :-

  • A body starts from Rest and travels with Uniform Acceleration of 2 m/s². If its Velocity is v after making a Displacement of 9 m . Then find the value of 'v' .

Answer :-

  • The value of Final Velocity is 6 m/s .

[tex] \rule {180pt} {2pt} [/tex]

Given :-

  • Initial Velocity = 0 m/s
  • Acceleration = 2 m/s²
  • Displacement = 9 m

To Find :-

  • Final Velocity = ?

Solution :-

As per the provided information in the given question, Initial Velocity is given 0 m/s . Acceleration is given 2 m/s² . Displacement is given 9 m . And, we have been asked to calculate the Final Velocity .

For calculating the Final Velocity , we will use 3ʳᵈ Equation of Motion :-

  • [tex] \sf {ᴠ ^{2} \: - \: ᴜ ^{2} \: = \: 2 \: ᴀs} [/tex]

Where ,

  • ᴠ² denotes to the Final Velocity
  • ᴜ² denotes to the Initial Velocity
  • ᴀ denotes to the Acceleration
  • s denotes to the Displacement

Therefore , by Substituting the given values in the above Equation :-

[tex] \longmapsto \: \: \sf {ᴠ ^{2} \: - \: ᴜ ^{2} \: = \: 2 \: \times \: ᴀ \: \times \: s} [/tex]

[tex] \longmapsto \: \: \sf {ᴠ ^{2} \: - \: 0 \: = \: 2 \: \times \: 2 \: \times \: 9} [/tex]

[tex] \longmapsto \: \: \sf {ᴠ ^{2} \: - \: 0 \: = \: 36} [/tex]

[tex] \longmapsto \: \: \sf {ᴠ ^{2} \: = \: 36} [/tex]

[tex] \longmapsto \: \: \sf {ᴠ \: = \: \sqrt { \: 36 \: }} [/tex]

[tex] \longmapsto \: \: \textbf {\textsf {ᴠ \: = \: 6}} [/tex]

Hence :-

  • Final Velocity = 6 m/s .

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