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The acceleration of free fall on a certain planet is 8.0 m s-2. An object gets dropped from a
height and hits the ground after 1.5 s. From what height must the object have been dropped?

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Answer:

  • Height from which the object is dropped is 9m

We are given that:

  • The acceleration of free fall on a certain planet is 8m/s². An object is dropped from the height and hits the ground after 1.5s

We need to find:

  • Height from which the object was dropped.

Using equations of motion:

➙ v² - u² = 2as

➙ v = u + at

here,

  • u = initial velocity

  • v = final velocity

  • a = acceleration

  • s = displacement

  • t = time taken

Solution:

From the given information, we can conclude that:

  • initial velocity of the object is 0 m/s

  • acceleration due to gravity = 8 m/s²

  • time taken = 1.5 seconds

Now, using equation of motion:

➝ v = u + at

➝ v = 0 + ( 8 × 1.5 )

➝ v = 0 + 12 .0

➝ v = 12 m/s

  • final velocity of object = 12 m/s

For, acceleration :

➝ v² - u² = 2as

➝ ( 12 )² - ( 0 )² = 2 × 8 × s

➝ 144 - 0 = 16s

➝ 16 s = 144

➝ s = 144 / 16

➝ s = 9m

  • Displacement = 9 m

[tex] \dag[/tex] Since, we take displacement in terms of distance in some places, therefore we can say that the height from which the object was dropped is 9 meters .

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