Respuesta :
Given :
- Base = 2 m and 6 m.
- Area = 60 m².
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To find :
- The height.
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Solution :
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We know,
[tex]{ \longrightarrow{\qquad \sf{ \pmb {\dfrac{1}{2 } \times (b_{1} + b_{2}) \times h = {Area_{(Trapezoid)} } }}}}[/tex]
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Now, Substituting the values :
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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{1}{2 } \times (2 + 6) \times h = {60 } }}}}[/tex]
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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{1}{2 } \times 8 \times h = {60 } }}}}[/tex]
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[tex]{ \longrightarrow{\qquad \sf{ {\dfrac{8}{2 } \times h = {60 } }}}}[/tex]
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[tex]{ \longrightarrow{\qquad \sf{ 4 \times h = {60 } }}}[/tex]
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[tex]{ \longrightarrow{\qquad \sf{ h = { \dfrac{60}{4} } }}}[/tex]
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[tex]{ \longrightarrow{\qquad \sf{ \pmb { h = {15} } }}}[/tex]
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Therefore,
- The height of the trapezoid is 15 m .
