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Guys, I’m giving you at least 100 points for you to answer to my last week of my math and geometric word problem homework paper. So guys, please listen up and pay attention to me without ignoring my last month’s math and geometric word problem homework paper for no reason! :D

There are 2 remaining geometric word problem questions that you need to answer in order for you to get a Brainliest award if your answers are the best with the best efforts and explanations.

The question #8 is the length of a rectangle is 30 centimetres less than three times the width. The perimeter of this rectangle is 180 centimetres. What are the dimensions of this rectangle?

word problem questions that you need to answer in order for you to get a Brainliest award if your answers are the best with the best efforts and explanations.


The question #9 is the perimeter of a triangle is 480 metres. The second side is 3 times the first and the third side is 60 metres more than the second. Please help me in order to find the dimensions of this triangle.

Please answer to my math word problem question as soon as possible with the best efforts and the best step-by-step explanations in order to get the Brainliest award of all the time! :D

Well anyways, guys, good luck on answering 2 remaining of my geometric word problem questions of my last week math and geometric word problem homework paper in order to get the best Brainliest award of all of the time, and I will check the answers to see if it’s appropriate for me. :)

Respuesta :

semsee45

Answer:

8) width = 30 cm

   length = 60 cm

9) first side = 60 m

   second side = 180 m

   third side = 240 m

Step-by-step explanation:

Question 8

Let W = width

Given:

  • length of a rectangle is 30 cm less than 3 times the width

⇒ Length = 3W - 30

Given:

  • Perimeter = 180 cm

Perimeter of a rectangle = 2W + 2L

(where W is the width and L is the length)

Substituting equation for length into the equation for the perimeter and solving for W:

   Perimeter = 2W + 2L

⇒ 180 = 2W + 2(3W - 30)

⇒ 180 = 2W + 6W - 60

⇒ 240 = 8W

⇒ W = 30 cm

Substitute found value of W into the equation for length and solve for length:

⇒ Length = 3(30) - 30

⇒ Length = 90 - 30

⇒ Length = 60 cm

Question 9

Given:

  • The second side is 3 times the first and the third side is 60 m more than the second.

Let x = first side

⇒ second side = 3x

⇒ third side = 3x + 60

Given:

  • Perimeter of triangle = 480 m

   Perimeter = sum of length of all sides

⇒ 480 = x + 3x + 3x + 60

⇒ 420 = 7x

⇒ x = 60

Therefore,

first side = 60 m

second side = 3 × 60 = 180 m

third side = 3(60) + 60 = 240 m

width be x

length=3x-30

Now

  • 2(3x-30+x)=180
  • 4x-30=90
  • 4x=120
  • x=30
  • 3x-30=60°

#2

sides be x,3x,3x+60

Now

  • x+3x+3x+60=480
  • 7x=420
  • x=60°

Hence

  • 3x=180
  • 3x+60=240

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