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A 60 kg ice-skater, travelling initially at 3.0 m / s, glides across a horizontal icy surface. The skater brakes and comes to rest after 5.0 m.

The work done against the braking force is the change in the kinetic energy of the skater

Respuesta :

Answer:

54 N

Explanation:

a= v/t

3÷5/3= 1.8 m/s^2

f=ma

1.8 x 60 = 108/2 = 54 N

The work done against the braking force is the change in the kinetic energy of the skater is 54 N.

What is work done?

Work is said to be done whenever a force moves an object over a distance.

[tex]W = F = ma[/tex]

where

Acceleration is given by

[tex]a = v/t[/tex]

[tex]a = \frac{3}{5/3}[/tex]

[tex]a = 1.8 m/s^2[/tex]

Work is

[tex]W = ma[/tex]

[tex]W = 60*1.8 m/s^2[/tex]

[tex]W = 54 N[/tex]

To learn more about Work here

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