Answer:
[tex]y^{10}-\dfrac{25}{64}x^2[/tex]
Step-by-step explanation:
Given expression:
[tex](\frac58x+y^5)(y^5-\frac58 x)[/tex]
Change the order of the terms in the first parentheses:
[tex]\implies (y^5+\frac58x)(y^5-\frac58 x)[/tex]
Apply the Difference of Two Squares: [tex](a+b)(a-b)=a^2-b^2[/tex]
[tex]\implies (y^5)^2-(\frac58x)^2[/tex]
Apply exponent rule [tex](a^b)^c=a^{b\cdot c}[/tex]
[tex]\implies y^{10}-(\frac58x)^2[/tex]
Apply exponent rule [tex]\left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}[/tex]
[tex]\implies y^{10}-\left(\dfrac{5^2}{8^2}x^2\right)[/tex]
[tex]\implies y^{10}-\dfrac{25}{64}x^2[/tex]
