can someone help pls

Answer:
x = ± 5
Step-by-step explanation:
for the figure to be an isosceles trapezoid
then the lower base angles must be congruent , that is
3x² - 4 = 2x² + 21 ( subtract 2x² from both sides )
x² - 4 = 21 ( add 4 to both sides )
x² = 25 ( take square root of both sides )
x = ± [tex]\sqrt{25}[/tex] = ± 5
Answer:
x=5
Step-by-step explanation:
Here,
→[tex]2x^{2} +21=3x^{2} -4\\\\[/tex]
→[tex]21+4=3x^{2} -2x^{2} \\[/tex]
→[tex]x^{2} =25[/tex]
→[tex]x=\sqrt{25}[/tex]
→[tex]x=5[/tex]
Let's check whether they are equal or not by putting the value of x.
→[tex]2x^{2} +21[/tex]
→[tex](2*5^{2}) +21[/tex]
→[tex]50+21[/tex]
→[tex]71[/tex]
→[tex]3x^{2} -4[/tex]
→[tex](3*5^{2} )-4[/tex]
→[tex]75-4[/tex]
→71
Hence they are equal.