Respuesta :
The longest interval (in seconds) Timer32 can measure if the system clock frequency (the one that feeds the timer) is 48MHz is 5.333 × 10⁻³ s
Since For Timer32, the largest possible Prescaler value is 256 and the smallest Prescaler value is 1, and we have a system clock frequency (the one that feeds the timer) is f = 48MHz = 48 × 10⁶ Hz
Period of the timer32
The period of the Timer32 is thus T = 1/f where f = frequency of system clock = 48 × 10⁶ Hz
So, substituting the value of f into the equation, we have
T = 1/f
T = 1/48 × 10⁶ Hz
T = 0.020833 × 10⁻⁶ s
T = 20.833 × 10⁻⁹ s
T = 20.833 ns
Longest time interval Timer32 can measure
Now the longest time interval the timer can measure, t = nT where
- n = maximum prescaler value = 256 and
- T = period of timer = 20.833 ns
So, substituting the values of the variables into theequation, we have
t = nT
t = 256 × 20.833 ns
t = 5333.248 ns
t = 5333.248 × 10⁻⁶ s
t = 5.333248 × 10⁻³ s
t ≅ 5.333 × 10⁻³ s
The longest interval (in seconds) Timer32 can measure if the system clock frequency (the one that feeds the timer) is 48MHz is 5.333 × 10⁻³ s
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