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A rubber ball (1 kg) falls from a height of 10 m and collides elastically with the floor. What is the velocity of the ball as it rebounds from the floor?

Respuesta :

hamzaahmeds

This question involves the concepts of the equation of motion and elastic collision.

The velocity of the ball as it rebounds from the floor will be "14 m/s".

REBOUND VELOCITY

The elastic collision is the one during which the momentum and kinetic energy of a body remain conserved. Hence, the velocity of the body also remains constant. Therefore, the rebound velocity of the ball will be the same as the striking velocity of the ball. This can be calculated using the third equation of motion.

[tex]2gh=v_f^2-v_i^2[/tex]

where,

  • h = height = 10 m
  • g = 9.81 m/s²
  • vf = striking velocity = rebound velocity = ?
  • vi = initial velocity = 0 m/s

Therefore,

[tex](2)(9.81\ m/s^2)(10\ m)=v_f^2-(0\ m/s)^2\\v_f=\sqrt{196.2\ m^2/s^2}\\\\v_f=14\ m/s[/tex]

Learn more about the equations of motion here:

https://brainly.com/question/5955789

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