Step-by-step explanation:
diameter of the sun divides the diameter of an helium atom.
helium atom = 0.000000000062 = 6.2 × 10^-11
Sun = 1,400,000,000 = 1.4 × 10^9
[tex] \frac{1.4 \times 10 {}^{ 9} }{6.2\times 10 {}^{ - 11} } [/tex]
[tex] \frac{1.4}{6.2} \times 10 {}^{9 + 11} [/tex]
[tex]0.225 \times 10 {}^{20} [/tex]
so therefore the diameter of the sun is 0.225 × 10^20 times bigger than the nucleus of an helium atom
