Respuesta :
you find the slope of the equation using y2-y1/x2-x1 and then you find the y intercept which is the point that crosses the y axis. Then you put that information into the slope intercept equation (y=mx+b m=slope b=y intercept)
at least i think thats what you are asking
at least i think thats what you are asking
First you need the slope, which is easily attainable by the change of x over the change of y
ex. with coordinates (x,y)(X,Y)
m=slope
m=[tex] \frac{ rise}{run} [/tex]
=[tex] \frac{ change x}{ change of y}[/tex]
= [tex] \frac{X-x}{Y-y} [/tex]
Then you will have every thing except the y intercept
(represented by b)
Using the slope-intercept form
and x and y being represented by the x, y values of a co-ordinate
y=mx+b
We can derive b
b= y-mx
Then when we have both m and b
Insert them into the form
ex. if m=-4, b=6
y=-4x+6
Taa daa!
If that helped please let me know
If it REALLY helped please rate as "Brainiest"
ex. with coordinates (x,y)(X,Y)
m=slope
m=[tex] \frac{ rise}{run} [/tex]
=[tex] \frac{ change x}{ change of y}[/tex]
= [tex] \frac{X-x}{Y-y} [/tex]
Then you will have every thing except the y intercept
(represented by b)
Using the slope-intercept form
and x and y being represented by the x, y values of a co-ordinate
y=mx+b
We can derive b
b= y-mx
Then when we have both m and b
Insert them into the form
ex. if m=-4, b=6
y=-4x+6
Taa daa!
If that helped please let me know
If it REALLY helped please rate as "Brainiest"