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A sample that weighs 107.75 g is a mixture of 30% helium atoms and 70% krypton atoms. How many particles are present in the sample?

Respuesta :

30% of 107.75 g is 32.325g so there are about 8.08125 mol of He which is
4.86 x 10^24 particles
70% of 107.75 g is 75.425g so there are about .9 mol of Kr which is 
5.42 x 10^23 paticles
In the whole sample, there are about 5.41 x 10^24 particles

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