Answer:
[tex]x=tan^{-1} (\frac{12}{5})[/tex]
Step-by-step explanation:
we know that
In the right triangle ABC of the figure
The measure of angle BAC is equal to angle x
Applying the sine
[tex]sin(x)=\frac{BC}{AB} =\frac{12}{13}[/tex]
[tex]x=sin^{-1} (\frac{12}{13})[/tex]
Applying the cosine
[tex]cos(x)=\frac{AC}{AB} =\frac{5}{13}[/tex]
[tex]x=cos^{-1} (\frac{5}{13})[/tex]
Applying the tangent
[tex]tan(x)=\frac{BC}{AC} =\frac{12}{5}[/tex]
[tex]x=tan^{-1} (\frac{12}{5})[/tex]
