Convert 4.77x10^24 molecules of SO2 to grams
It solves it but I don't think that the right answer

507.672 g of [tex]SO_2[/tex] is present in 4.77x[tex]10^{24}[/tex] molecules.
A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Mole of [tex]SO_2[/tex] = 4.77 x [tex]10^{24}[/tex] molecules ÷ 6.02214076 × [tex]10^{23}[/tex]
7.92
Now converting moles into grams:
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]7.92 = \frac{mass}{64.1 g/mol}[/tex]
Mass = 507.672 g
Hence, 507.672 g of [tex]SO_2[/tex] is present in 4.77x[tex]10^{24}[/tex] molecules.
Learn more about moles here:
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