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What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

y+6=−1411(x−4)

y+6=−23(x−4)

y−6=−1411(x+4)

y−6=−23(x+4)

Respuesta :

texaschic101
(7,-8)(-4,6)
slope = 6 - (-8) / (-4 - 7) = (6 + 8) / -11 = -14/11

point slope : y - y1= m(x - x1)
(-4,6)...x1 = -4 and y1 = 6
now we sub
y - 6 = -14/11(x - (-4) =
y - 6 = -14/11(x + 4) <===
lublana

Answer:

C.[tex]y-6=-\frac{14}{11}(x+4)[/tex]

Step-by-step explanation:

We are given that a line passes through the points (7,-8) and (-4,6).

We have to find the equation in point-slope form of a line .

Slope formula:[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Using the formula

Slope of line=[tex]m=\frac{6+8}{-4-7}[/tex]

Slope of line=[tex]m=\frac{14}{-11}[/tex]=[tex]-\frac{14}{11}[/tex]

Point-slope form: [tex]y-y_1=m(x-x_1)[/tex]

Substitute the values then we get

Equation of line which passing through the point (-4,6) with slope -14/11

[tex]y-6=-\frac{14}{11}(x+4)[/tex]

Hence option C is true.

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