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What is the Area of a right triangle as a function of the base b if the base of the triangle is twice its height?

Respuesta :

Amy1459
The base is twice the height, or b = 2h. So, h = b/2. The area of a right triangle is (1/2)*b*h, and replacing h with b/2 you have (1/2)*b*(b/2), or (1/4)*b^2.So to write this it is A(b) = (1/4)*b^2 for b >= 0

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