Respuesta :

NavyShadeRose
Well, in order to get 145, you'd need to add up 15, 27, 29, 31,  and 33.
The third number in this sequence is 29, so... there you have it.
calculista

Let

x-------> the first odd number

x+2----> the second consecutive odd number

x+4----->  the third consecutive odd number

x+6----->  the fourth consecutive odd number

x+8----->  the fifth  consecutive odd number

we know that

[tex]x+(x+2)+(x+4)+(x+6)+(x+8)=145[/tex]

Solve for x

[tex]5x+20=145[/tex]

[tex]5x=145-20[/tex]

[tex]5x=125[/tex]

[tex]x=25[/tex]

so

The sequence is

[tex]25,27,29,31,33[/tex]

therefore

the answer is

The third number in the sequence is the number [tex]29[/tex]



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