The half-life of carbon-14 is 5370 years. The carbon-14 levels in a fossil indicate that 6 half-lives have passed. How old is the fossil?

32,220 years
75,200 years
50,000 years
35,000 years

Respuesta :

zhduch
On half life is 5370 years; 6 half lives have passed. You just multiply,

5370*6 = 32,220 years

Answer: 35,000 years

Explanation: Radioactive process follow first order kinetics.

To calculate the rate constant, we use the formula:

[tex]k=\frac{0.693}{t_{1/2}}[/tex]

[tex]k=\frac{0.693}{5370years}}[/tex]

[tex]k=1.2\times 10^{-4} years^{-1}[/tex]

Also : [tex]a=\frac{a_o}{2^n}[/tex]

where,  

a = amount of reactant left after n-half lives

[tex]a_o[/tex] = Initial amount of the reactant

n = number of half lives = 6

Putting values in above equation, we get:

[tex]2^6=\frac{a_0}{a}[/tex]

[tex]64=\frac{a_0}{a}[/tex]

The rate expression for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a_0}{a}[/tex]

where,

k = rate constant

t = time taken for decay process

[tex]a_0[/tex]  = initial amount of the reactant

a = amount left after decay process

Putting values in above equation, we get:

[tex]t=\frac{2.303}{1.2\times 10^{-4}}\log{64}[/tex]

[tex]t=35000years[/tex]