Answer:
Option C is correct.
Step-by-step explanation:
Given two numbers
[tex]10\times 10^9\text{ and } 99\times 10^6[/tex]
we have to estimate about many times a number larger than another.
To estimate we have to divide.
[tex]\frac{10\times 10^9}{99\times 10^6}[/tex] → (1)
As [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]
Equation (1) implies
[tex]\frac{10\times 10^{9-6}}{99}[/tex]
⇒ [tex]\frac{10\times 10^3}{99}[/tex]
⇒ [tex]\frac{10000}{99}=101.01\sim 100\thinspace times[/tex]
Hence, 100 times larger.
Option C is correct.
