Respuesta :
Answer: The required equation of the concentric circle is
[tex]x^2+y^2+10x-8y+40=0.[/tex]
Step-by-step explanation: Given that a circle is centered at the point C(-5,4) and has a radius of 2 units.
We are to find the equation of a concentric circle with half the radius.
We know that
the standard equation of a circle with center at the point (h, k) and radius 'r' units is given by
[tex](x-h)^2+(y-k)^2=r^2~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
Since the centers of two concentric circles are same, so the center of the circle will be
center, (h, k) = (-5, 4) and radius is equal to half of 2 units.
So, radius of the concentric circle will be
[tex]r=\dfrac{2}{2}=1~\textup{unit}.[/tex]
Therefore, the equation of the concentric circle is
[tex](x-h)^2+(y-k)^2=r^2\\\\\Rightarrow (x-(-5))^2+(y-4)^2=1^2\\\\\Rightarrow (x+5)^2+(y-4)^2=1\\\\\Rightarrow x^2+10x+25+y^2-8y+16=1\\\\\Rightarrow x^2+y^2+10x-8y+40=0.[/tex]
Thus, the required equation of the concentric circle is
[tex]x^2+y^2+10x-8y+40=0.[/tex]
