Anonymuz04
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A CD of classical guitar music contains 5 songs. The length of each song is shown in the table; Track 1 is 6.5 minutes, Track 2 is 8 minutes, Track 3 is 3.93 minutes, Track 4 is 4.1 minutes, and Track 5 is 5.05 minutes: Part A between each song is a 0.05 minute break. How long is does it take to listen to the CD from the beginning of the first song to the end of the last song? Part B Juan wants to buy the CD from an internet music site. He downloads the CD onto a disc that can hold up to 60 minutes of music. How many more minutes of music can he still buy after downloading the CD?

Respuesta :

Part A - 27.78 minutes. Add all the times together including the 0.05 break that is repeated four times.
Part B - 32.22 minutes. Subtract 27.78 from 60.
calculista

Answer:

Part A) [tex]27.78\ min[/tex]

Part B) [tex]32.22\ min[/tex]

Step-by-step explanation:

Part A)

Let

[tex]t1=6.5\ min[/tex] ----> length song [tex]1[/tex]

[tex]t2=8\ min[/tex] ----> length song [tex]2[/tex]

[tex]t3=3.93\ min[/tex] ----> length song [tex]3[/tex]

[tex]t4=4.1\ min[/tex] ----> length song [tex]4[/tex]

[tex]t5=5.05\ min[/tex] ----> length song [tex]5[/tex]

[tex]b=0.05\ min[/tex] -----> break between each song

we know that

The length of the CD is equal to

[tex](t1+t2+t3+t4+t5)+4(b)[/tex]

substitute the values

[tex](6.5+8+3.93+4.1+5.05)+4(0.05)=27.58+0.20=27.78\ min[/tex]

Part B)

Subtract the total length of the CD from [tex]60[/tex] minutes of music

so

[tex](60-27.78)=32.22\ min[/tex]

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