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The Sierpinski Triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape. A series of these triangles is shown below, starting with an area of 64. If we remove 1/4 of the area what fraction of the area remains?

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MissPhiladelphia
The Sierpinski Triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape.
starting with an area of 64. If we remove 1/4 of the area 
so the removed area = 64* ( 1/4) = 16
remaining area = 64 - 16 = 48

fraction of the remaining area = 48 / 64 = 3/4
or another way 1 - 1/4 = 3/4

The fraction of the area that remains should be [tex]\frac{3}{4}[/tex]

Calculation of the fraction:

Since an equilateral triangle has 1/4 of its area removed to create a new shape. A series of these triangles is shown below, starting with an area of 64.

Now the removed area should be

[tex]= 64\times ( 1/4)[/tex]

= 16

So, remaining area = 64 - 16 = 48

Now

fraction of the remaining area [tex]= 48 / 64 = 3/4[/tex]

Therefore, The fraction of the area that remains should be [tex]\frac{3}{4}[/tex]

Learn more about an area here: https://brainly.com/question/24364874

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