Which of the following can be determined about events A and C from the table.

A. P(A | C) = 0.16, P(A) = 0.16, the events are independent

B. P(A | C) = 0.16, P(C) = 0.16, the events are independent

C. P(C | A) = 0.75, P(C)=0.75 the events are not independent

D. P(C | A) = 0.75, P(A)=0.75 the events are not independent

Which of the following can be determined about events A and C from the table A PA C 016 PA 016 the events are independent B PA C 016 PC 016 the events are indep class=

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The correct answer for this question is this one: "C. P(C | A) = 0.75, P(C)=0.75 the events are not independent." 

The statement that can be determined about events A and C from the table is that P(C | A) = 0.75, P(C)=0.75 the events are not independent. Hope this helps answer your question.

Answer:

Option: A is the correct answer.

       A. P(A | C) = 0.16, P(A) = 0.16, the events are independent

Step-by-step explanation:

We know that two events A and B are said to be independent if:

[tex]P(A|B)=P(A)[/tex]

(

Since, we know that if A and B are two independent events then

[tex]P(A\Bigcap B)=P(A)\cdot P(B)------------(1)[/tex]

and:

[tex]P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}[/tex]

and hence using property (1) we get:

[tex]P(A|B)=P(A)[/tex]   )

from the given table we have:

[tex]P(A|C)=\dfrac{P(A\bigcap C)}{P(C)}\\\\\\P(A|C)=\dfrac{0.12}{0.75}\\\\\\P(A|C)=0.16[/tex]

and also, P(A)=0.16

As P(A|C)=P(A)

     Hence, events A and C are independent.

Also we may observe that:

[tex]P(C|A)=P(C)[/tex]

(

Since, from table we have:

P(C)=0.75

and

[tex]P(C|A)=\dfrac{P(A\bigcap B)}{P(A)}\\\\\\P(C|A)=\dfrac{0.12}{0.16}\\\\P(C|A)=0.75[/tex] )

Hence, events A and C are independent.