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The 50th term of an arithmetic sequence is 86 and the common difference is 2.  Find the first three terms of the sequence.

Respuesta :

LammettHash
[tex]a_n=a_{n-1}+d=a_{n-2}+2d=\cdots=a_1+(n-1)d[/tex]

which means

[tex]a_{50}=86=a_1+49\times2\implies a_1=-12[/tex]

which in turn means the next two terms are [tex]a_2=-10[/tex] and [tex]a_3=-8[/tex].

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