Find a solution to the following system of equations. –2x + 5y = 8 2x + 2y = 6

A. (1, 2)

B. (0, 3)

C. (–2, 1)

D. (2, 1)

Respuesta :

-2x + 5y = 8
2x + 2y = 6
----------------add
7y = 14
y = 14/7
y = 2

2x + 2y = 6
2x + 2(2) = 6
2x + 4 = 6
2x = 6 - 4
2x = 2
x = 2/2
x = 1

solution is (1,2)
Add the two equations to eliminate x:
-2x + 5y = 8
                     +
 2x + 2y = 6
                     =
7y = 14   so y = 2.
Sub y into an equation as 2, so if you take the 2nd equation you get:
2x + (2*2) = 6, so 2x = 2, x=1.