The number of people who voted follows a binomial distribution with probability of having voted [tex]p=0.22[/tex] and [tex]n=150[/tex] subjects, which means the approximating normal distribution should have mean [tex]np=33[/tex] and standard deviation [tex]\sqrt{np(1-p)}\approx5.07[/tex].
With the continuity correction, you have
[tex]\mathbb P(X<39)\approx\mathbb P(X<38.5)=\mathbb P\left(\dfrac{X-33}{5.07}<\dfrac{38.5-33}{5.07}\right)=\mathbb P(Z<1.08)\approx0.86[/tex]
