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A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

Respuesta :

JcAlmighty
The answer is 314.6 K

Gay-Lussac’s law:
PV = kT
P - pressure
V - volume
T - temperature
k - constant

k = PV/T = P1 * V1 / T1 = P2 * V2 / T2 = ...

P1 * V1 / T1 = P2 * V2 / T2
P1 = 1.1 atm
V1 = 7 L
T1 = 285 K
P2 = 1.1 atm - 0.6 atm = 0.5 atm
V2 = 7 L + 10 L = 17 L
T2 = ?

1.1 * 7 / 285 = 0.5 * 17 / T2
7.7 / 285 = 8.5 / T2
T2 = 8.5 * 285 / 7.7
T2 = 314.6 K

Answer:

222.1

Explanation:

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