The average (arithmetic mean) weight of the students in the French Club is 150 pounds, and the average weight of the students in the Spanish Club is 130 pounds. If no one is a member of both clubs, if the average weight of all the students is 142 pounds, and if there are 30 members in the French Club, how many members are there in the Spanish Club?

Respuesta :

20 members are in the spanish club

Members in the Spanish Club are  [tex]20[/tex] .

What is average (arithmetic mean) ?

Average (arithmetic mean) or arithmetic average, or simply just the mean or the average, is the sum of a collection of numbers divided by the count of numbers in the collection.

Average [tex]= \frac{Sum \ of \ all \ numbers}{Total \ numbers}[/tex]

We have,

Let Members in the Spanish Club [tex]=x[/tex]

Let Members in the French Club[tex]=z=30[/tex]

Let Total number of students [tex]=y=x+z[/tex]

The average weight of the students in the French Club is [tex]150[/tex] pounds .

The average weight of the students in the Spanish Club is [tex]130[/tex] pounds .

The average weight of all the students is [tex]142[/tex] pounds .

So,

Average [tex]= \frac{Sum \ of \ all \ numbers}{Total \ numbers}[/tex]

Average weight of students in the French Club [tex]= \frac{Sum \ of \ weights}{Total \ numbers \ of \ student}[/tex][tex]150=\frac{Sum \ of \ weights}{30}[/tex]

Sum  of  weights [tex]=4500[/tex]

The average weight of all the students = Average weight of students in (French Club + Spanish Club)

so,

[tex]142(x+z)=150*z+130*x[/tex]

[tex]142(30+x)=150*30+130x[/tex]

[tex]4260+142x=4500+130x[/tex]

[tex]12x=240[/tex]

[tex]x=20[/tex]

So, Members in the Spanish Club are [tex]20[/tex] .

Hence, we can say that the members in the Spanish Club are  [tex]20[/tex] .

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