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Use the distance formula to find the distance, to the nearest tenth, from S(6, −2) to V(−4, 3). −5.0 units 3.1 units 11.2 units 8.7 units

Respuesta :

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ S(\stackrel{x_1}{6}~,~\stackrel{y_1}{-2})\qquad V(\stackrel{x_2}{-4}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ SV=\sqrt{[-4 - 6]^2 + [3 - (-2)]^2}\implies SV=\sqrt{(-10)^2+(3+2)^2} \\\\\\ SV=\sqrt{125}\implies SV\approx 11.18\implies \underset{\textit{rounded up}}{SV\approx 11.2}[/tex]

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