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How to solve exponential equations with constant prime numbers or number whos fractors are primes?
Example: 3^x+2+3^x−3=244

Respuesta :

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

[tex]3^{x+2}+3^{x-3}=244[/tex]

[tex]3^x3^2+\frac{3^x}{3^3} =244[/tex]

[tex]3^x(9+\frac{1}{27})=244 [/tex]

[tex]3^x(\frac{244}{27})=244 [/tex]

[tex]3^x=27[/tex]

[tex]x=log_3(27)[/tex]

[tex]x=3[/tex]

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