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In humans, normal color vision is dominant over colorblindness. A colorblind male marries a female who is a carrier for color blindness. What is the probability that a colorblind child would be born to these parents?

Respuesta :

there is a 50% chance that they would give birth to a colorblind child 

Answer:

There is a 50% probability that a colorblind child would be born.

Explanation:

The carrier female (Vv, heterozygous for blindness) will give a normal vision allele to half of the descendants (V) and a blindness allele to the other half of the descendants (v). The blind male (vv, homozygous for blindness) will give the blindness allele to all the descendants. Then, half descendants will be Vv (heterozygous) and the other half will be homozygous for the blindness allele. Only homozygous will be blind because the blindness allele is recessive: 50% of the descendants.