Answer:
- slope-intercept: y = 2x +8
- point-slope: y -4 = 2(x +2)
- standard: 2x -y = -8
Step-by-step explanation:
The slope of the line between the two points can be found from the formula ...
m = (y2 -y1)/(x2 -x1)
m = (6 -4)/(-1 -(-2)) = 2/1 = 2
The point-slope equation is ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
Using the found slope and the first given point, the point-slope equation can be written ...
y -4 = 2(x +2) . . . . point-slope equation of the line
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Solving this equation for y gives the slope-intercept form:
y = 2x +4 +4 . . . . . add 4 to both sides, eliminate parentheses
y = 2x +8 . . . . slope-intercept equation of the line
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Putting the variable terms on the opposite side of the equal sign from the constant gives standard form. The leading coefficient must be positive, so we do this by subtracting y+8 from both sides.
2x -y = -8 . . . . standard form equation of the line
