The number of mole of carbon in 18.27 g of alanine is 0.615 mole
Determination of the mole of 18.27 g of alanine
- Molar mass of C₃H₇NO₂ = (3×12) + (7×1) + 14 + (2×16) = 89 g/mol
- Mass of C₃H₇NO₂ = 18.27 g
Mole = mass / molar mass
Mole of C₃H₇NO₂ = 18.27 / 89
Mole of C₃H₇NO₂ = 0.205 mole
How to determine the number of mole carbon in 18.27 g (i.e 0.205 mole) of alanine
Alanine => C₃H₇NO₂
From the formula of alanine,
1 mole of C₃H₇NO₂ contained 3 moles of C.
Therefore,
0.205 mole of C₃H₇NO₂ will contain = 0.205 × 3 = 0.615 mole of C
Thus, 0.615 mole of C is present in 18.27 g (i.e 0.205 mole) of alanine.
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