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WILL MARK BRAINLIEST !!! 100 POINTS !!!
A picture frame has a perimeter of 40 inches. Its length is 2 inches greater than one-half its width. Let w represent the width in inches of the picture frame, and let l represent the length in inches. Which system of equations can be used to find the dimensions of the picture frame?

Respuesta :

  • Let width be w
  • Length=w/2+2=w+4/2

ATQ

[tex]\\ \sf\longmapsto 2(w+\dfrac{w+4}{2})=40[/tex]

[tex]\\ \sf\longmapsto2( \dfrac{2w+w+4}{2})=40[/tex]

[tex]\\ \sf\longmapsto 3w+4=40[/tex]

[tex]\\ \sf\longmapsto 3w=36[/tex]

[tex]\\ \sf\longmapsto w\approx 12[/tex]

  • L=14
mhanifa

Answer:

  • See below

Step-by-step explanation:

Convert the given details into equations

A picture frame has a perimeter of 40 inches:

  • 2(l + w) = 40

Its length is 2 inches greater than one-half its width:

  • l = 1/2w + 2

The two equations above make the system to solve for dimensions.

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