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explain how you got ur answer pls
Out of 50 randomly chosen football players in a football league, 10 said they were going to attend camp. There are 800 players in the entire league.
How many players in the league would you expect to attend camp?

Respuesta :

Using the binomial distribution, it is found that you would expect 160 players in the league to attend camp.

For each player, there are only two possible outcomes, either they attend camp, or they do not. The probability of a player attending camp is independent of any other player, hence, the binomial distribution is used to solve this question.

What is the binomial probability distribution?

  • It is the probability of exactly x successes on n repeated trials, with p probability of a success on each trial.
  • The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

In this problem:

  • 10 out of 50 players said they would attend camp, hence [tex]p = \frac{10}{50} = 0.2[/tex].
  • There are 800 players in the entire league, hence [tex]n = 800[/tex].

Then, the expected number is:

[tex]E(X) = np = 800(0.2) = 160[/tex]

You can learn more about the binomial distribution at https://brainly.com/question/14424710

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