He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
According to the principle of conservation of linear momentum, the total momentum of a system is constant. Hence;
Total momentum before = (42.00 kg + 2.00 kg) 1.20 m/s = 52.8 Kgm/s
Total momentum after = (42.00 kg × v) + (2.00 kg × 0) = 42.00 v Kgm/s
Applying the law of conservation of linear momentum;
52.8 Kgm/s = 42.00 v Kgm/s
v = 52.8/42.00
v = 1.26 m/s
He jumped off with a velocity of 1.26 m/s in the same direction as the skateboard .
Learn more about linear momentum:https://brainly.com/question/2141713
