This problem is providing us with the molarity of calcium chloride solution as 1.0 M and its volume as 0.500 L so the mass of the solute is required and found to be 55.49 g according to:
In chemistry, units of concentration are used to represent the relative amounts of solute and solvent that are present in a solution. In such a way, this particular case is referred to molarity, which is defined as moles of solute divided by volume of solution in liters:
[tex]M=\frac{n}{V}[/tex]
Thus, given the molarity and volume, we can calculate the moles as a first approach to the required:
[tex]n=1.0\frac{mol}{L}*0.500L\\\\n=0.50mol[/tex]
Finally, we multiply this result by the molar mass of calcium chloride to obtain the required mass:
[tex]m=0.50mol*\frac{110.98g}{1mol} \\\\m=55.49g[/tex]
Learn more about molarity: https://brainly.com/question/10053901
