Answer:
3
Step-by-step explanation:
The distance formula is:
[tex]d = \sqrt {\left( {x_2 - x_1 } \right)^2 + \left( {y_2 - y_1 } \right)^2 }[/tex]
Now we can plug the coordinates into the equation
[tex]d = \sqrt {\left({8 - 5 \right)^2 + \left( {10 - 10 } \right)^2 }[/tex]
Then we simplify
[tex]d = \sqrt {\left 3 \right^2 + \left 0 \right^2 }[/tex]
[tex]d=\sqrt{9+0} [/tex]
[tex]d=\sqrt{9} [/tex]
[tex]d=3[/tex]
Answer:
the distance between (5,10) and (8,10) is 3.
Step-by-step explanation:
Here's the required formula to find distance between (5,10) and (8,10) :
[tex]\implies{\small{\pmb{\sf{d = \sqrt{\Big(x_{2} - x_{1} \Big)^{2} + \Big(y_{2} - y_{1} \Big)^{2}}}}}}[/tex]
Here, we have provided :
[tex]\begin{gathered}\begin{gathered} \footnotesize\rm {\underline{\underline{Where}}}\begin{cases}& \sf x_2 = 8\\ & \sf x_1 = 5\\ & \sf y_2 = 10\\& \sf y_1 = 10\end{cases} \end{gathered}\end{gathered}[/tex]
Substituting all the given values in the formula to find the distance between (5,10) and (8,10):
[tex]\implies{\small{\sf{d = \sqrt{\Big(x_{2} - x_{1} \Big)^{2} + \Big(y_{2} - y_{1} \Big)^{2}}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{\Big(8 - 5 \Big)^{2} + \Big(10 - 10\Big)^{2}}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{\Big( \: 3 \: \Big)^{2} + \Big( \: 0 \: \Big)^{2}}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{\Big(3 \times 3 \Big)+ \Big(0 \times 0\Big)}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{\big( \: 9 \: \big)+ \big( \: 0 \: \big)}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{9 + 0}}}}[/tex]
[tex]\implies{\small{\sf{d = \sqrt{9}}}}[/tex]
[tex]\implies{\sf{\underline{\underline{\red{d = 3}}}}}[/tex]
Hence, the distance between (5,10) and (8,10) is 3.
[tex]\rule{300}{2.5}[/tex]
