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An object is traveling at a constant velocity of 8.6 m/s (v0) when it experiences a constant acceleration of 2.1 m/s^2 (a) for a time of 17 s (t). What will its velocity (v) be after that acceleration?

Respuesta :

MichaelAladejobi

Answer:

velocity = 44.3m/s

Explanation:

From the law of motion.

v = u + at

v = 8.6 + (2.1 x 17)

v = 8.6 + (35.7)

v = 44.3m/s after 2.1m/s²

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